Question
Je recherche il y a quelque temps comment analyser css et j'ai trouvé ExCSS https://github.com/TylerBrinks/ExCSS
J'ai un fichier HTML. et j'ai besoin d'obtenir le style de police de csFC2BB1D1
qui est en italic
afin de lire le code HTML. J'utilise htmlagility pack. et j'utilise ExCSS pour analyser le css
et voici mon code
HtmlDocument doc = new HtmlDocument();
doc.Load(htmlLocation);
var parser = new Parser();
var data = doc.DocumentNode.Descendants("style").FirstOrDefault();
var stylesheet = parser.Parse(data.OuterHtml);
foreach (var item in stylesheet.StyleRules
.Select(r => r.Selector)) {
Console.WriteLine(item);
}
la sortie de l'instruction de boucle est
style type>.csC67CFA75
.cs3B0A1ABE
.cs6B2A4BAA
.cs7FB5C607
.csB0E2188C
.cs619CFE26
.cs80D9435B
.csE163F6C2
.cs5B41FA1C
.csC4CFBF3A
.csFC2BB1D1
.csC8468922
.cs21FA5D81
.cs95A8AE3D
.csCC736C83
.cs116BBDE0
.cs137E84BF
.cs6E4FDAEF
.cs92C3DA2B
.cs794D75A2
.csE6E4F8C4
et pourquoi affiche-t-il également le style type> texte style type> et pas seulement le selector
et ceci est mon document html
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" /><title>
</title>
<style type="text/css">
.csC67CFA75{text-align:center;text-indent:36pt;margin:0pt 0pt 0pt 0pt}
.cs3B0A1ABE{color:#000000;background-color:transparent;font-family:Times New Roman;font-size:14pt;font-weight:normal;font-style:normal;}
.cs6B2A4BAA{color:#000000;background-color:transparent;font-family:Times New Roman;font-size:6.5pt;font-weight:normal;font-style:normal;}
.cs7FB5C607{text-align:justify;text-indent:36pt;margin:0pt 0pt 0pt 0pt}
.csB0E2188C{color:#000000;background-color:transparent;font-family:Times New Roman;font-size:14pt;font-weight:bold;font-style:normal;}
.cs619CFE26{color:#000000;background-color:transparent;font-family:Times New Roman;font-size:14pt;font-weight:normal;font-style:italic;}
.cs80D9435B{text-align:justify;text-indent:0pt;margin:0pt 0pt 0pt 0pt}
.csE163F6C2{color:#000000;background-color:transparent;font-family:Times New Roman;font-size:14pt;font-weight:bold;font-style:italic;}
.cs5B41FA1C{color:#000000;background-color:transparent;font-family:Times New Roman;font-size:9pt;font-weight:normal;font-style:normal;}
.csC4CFBF3A{color:#000000;background-color:transparent;font-family:Courier New;font-size:9pt;font-weight:normal;font-style:normal;}
.csFC2BB1D1{color:#000000;background-color:transparent;font-family:Times New Roman;font-size:20pt;font-weight:normal;font-style:italic;}
.csC8468922{color:#000000;background-color:transparent;font-family:Times New Roman;font-size:11pt;font-weight:normal;font-style:italic;}
.cs21FA5D81{text-align:right;text-indent:36pt;margin:0pt 0pt 0pt 0pt}
.cs95A8AE3D{color:#FF0000;background-color:transparent;font-family:Times New Roman;font-size:14pt;font-weight:normal;font-style:normal;}
.csCC736C83{color:#000000;background-color:transparent;font-family:Times New Roman;font-size:9pt;font-weight:normal;font-style:italic;}
.cs116BBDE0{color:#000000;background-color:transparent;font-family:Times New Roman;font-size:7pt;font-weight:normal;font-style:normal;}
.cs137E84BF{text-align:justify;text-indent:0pt;margin:0pt 36pt 0pt 36pt}
.cs6E4FDAEF{color:#000000;background-color:#FFFF00;font-family:Times New Roman;font-size:14pt;font-weight:normal;font-style:normal;}
.cs92C3DA2B{color:#000000;background-color:transparent;font-family:Times New Roman;font-size:14pt;font-weight:normal;font-style:normal;text-decoration: underline;}
.cs794D75A2{color:#FFFF00;background-color:transparent;font-family:Times New Roman;font-size:9pt;font-weight:normal;font-style:normal;}
.csE6E4F8C4{color:#000000;background-color:transparent;font-family:Times New Roman;font-size:8pt;font-weight:normal;font-style:normal;}
</style>
</head>
<body>
</body>
</html>
Réponse acceptée
Parce que vous passez non seulement le CSS, mais aussi la balise de style parent à l’analyseur. Vous devriez avoir juste passé le contenu du style en utilisant InnerHtml au lieu de OuterHtml . Vous pouvez ensuite procéder comme suit pour obtenir le style de police cible:
// find among the CSS rules
var fontStyle = stylesheet.StyleRules
// rule for class `csFC2BB1D1`
.Where(r => r.Selector.ToString() == ".csFC2BB1D1")
// then select the value for `font-style`
.Select(o => o.Declarations.First(p => p.Name == "font-style").Term.ToString())
.First();
Je préfère la syntaxe de requête pour dans ce scénario cependant:
var query = from rule in stylesheet.StyleRules
where rule.Selector.ToString() == ".csFC2BB1D1"
from declaration in rule.Declarations
where declaration.Name == "font-style"
select declaration.Term.ToString();
var fontStyle = query.FirstOrDefault();
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