Question
I have following html snippet:
<div class="rsw-pp rsw-pp-widget">
<div g:type="AverageStarRating" g:secondaryurls="http://maps.google.com/?cid=12948004443906002997" g:decorateusingsecondary="http://maps.google.com/?cid=12948004443906002997" g:groups="maps" g:rating_override="2.998000" class="rsw-stars "> </div>
</div>
I'd like to get innerhtml of the first div. The expected result is:
<div g:type="AverageStarRating" g:secondaryurls="http://maps.google.com/?cid=12948004443906002997" g:decorateusingsecondary="http://maps.google.com/?cid=12948004443906002997" g:groups="maps" g:rating_override="2.998000" class="rsw-stars "> </div>
How can I do that? Ex <xsl:value-of select="//div[@class='rsw-pp rsw-pp-widget']/html()" />
This will not work because there's no html() function. Could anyone help me?
Accepted Answer
Use:
//div[@class='rsw-pp rsw-pp-widget']/node()
This selects any node (element, text-node, processing instruction or comment-node) that is a child of any element selected by the expression //div[@class='rsw-pp rsw-pp-widget'].
XSLT verification:
This transformation:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="/">
<xsl:copy-of select=
"//div[@class='rsw-pp rsw-pp-widget']/node()"/>
</xsl:template>
</xsl:stylesheet>
when applied on the provided XML document (corrected to be wellformed):
<div class="rsw-pp rsw-pp-widget">
<div xmlns:g="g:g"
g:type="AverageStarRating"
g:secondaryurls="http://maps.google.com/?cid=12948004443906002997"
g:decorateusingsecondary="http://maps.google.com/?cid=12948004443906002997"
g:groups="maps" g:rating_override="2.998000" class="rsw-stars "></div>
</div>
selects and outputs exactly the wanted nodes:
<div xmlns:g="g:g" g:type="AverageStarRating"
g:secondaryurls="http://maps.google.com/?cid=12948004443906002997"
g:decorateusingsecondary="http://maps.google.com/?cid=12948004443906002997"
g:groups="maps" g:rating_override="2.998000" class="rsw-stars "/>
Popular Answer
As you've found, XSLT does not have an html() method. Your select statement is just about right. If you remove the /html() you'll have selected the <div> element you're and using <xsl:value-of> will output all of the node's contents.
If you're using thsi in the context of the HtmlAgilityPacl (as you've tagged it) then follow Oded's approach (with a slightly modified select):
var outerDivNode = doc.DocumentNode.SelectSingleNode("//div[@class='rsw-pp rsw-pp-widget']");
var innerDivText = outerDivNode.InnerHtml;